Question

1)-2t^2+8t+2=0 2)x2-10x-39=0

Answer 1

-2t^2+8t+2=0

D= 8*8+4*2*2=64+16=80;

t1=(-8+(корень 80))/(-4);

t2=(-8-(корень 80))/(-4);

x2-10x-39=0

x1+x2=10;

x1*x2=-39;

x1=13

x2=-3