1) (2^32*(-2)^(-3)*(-2^7)^6)(-(-2^7)2)=2^(32-3-42-14)=2^(-17)
2)1/24+(57/25+18/25)/(8-5)*(4/49-4/7)^(-1)=1/24+3/3*((4-28)/49)^(-1)=1/24+49/24=-48/24=-2
3)√25/4-√196/144+√625/484=5/2-16/12+25/22=(165-88+75)/66=126/33=3 9/11
4) 8z^4*√(2z) *4z^2 *√(2z)=32z^6*2z=64z^7
(9+√65)^1/4 * (9-√65)^1/4=(9^2-65)^1/4=(81-65)^1/4=16^1/4=2
2y-6y^1/2+6^1/2=2y
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2.
(3-√7) = <span>√1/2 п4, k э Z</span>
По теореме, обр. теореме Виета
n1+n2=-10
n1*n2=21
n1=-7
n2=-3
Ответ:-7;-3.