7(2а+1)/3(а+2b)
Тут нечего сокращать
А) 4х+12=5х+10
9х=-2
х=-2/9
б) -2х+10+3х-12=4х+1
-3х=-1
х=1/3
в) 3х-3=2х+4
5х=7
х=1 2/5
г) 3х-15-2х-8=-5х+1
6х=24
х=24:6
х=4
<span>1) f(x)=√3x+1, x0=5;
</span>
<span>f'(5) = 3/(2sqrt(16)) = 3/8
2) f(x) = sin^5x, x0=π/3
f'(x) = 5cos(5x)
f'(</span>π/3) = 5cos(5π/3) = 5cos(2π-π/3) = 5cos(π/3) = 5/2
(0.2)^-6
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