Question

ЛОГАРИФМ.ПОЖАЛУЙСТА:>

Answer 1

1)
$log_{0.5}27=log_{ \frac{1}{2} }27=log_{2^{-1}}27=-log_{2}27= \\ \\ =-log_{2}3^3=-3log_{2}3 \\ \\ \\ -3log_{2}3=a \\ log_{2}3=- \frac{a}{3}$

2)
$log_{ \sqrt{3} } \sqrt[6]{1.5}=log_{3^{ \frac{1}{2} }}(1.5^{ \frac{1}{6} })= \frac{1}{6}: \frac{1}{2} log_{3}1.5= \\ \\ = \frac{1}{3}log_{3}( \frac{3}{2} )= \frac{1}{3}(log_{3}3-log_{3}2)= \\ \\ = \frac{1}{3}(1-log_{3}2)= \frac{1}{3}(1- \frac{1}{log_{2}3} )$

3)
$\frac{1}{3}(1- \frac{1}{- \frac{a}{3} } )= \frac{1}{3}(1+ \frac{3}{a} )= \frac{1}{3}+ \frac{1}{a}= \frac{1}{3}+a^{-1}$

Ответ: 3)