У=√х+1: 1; 1/2+1=3/2; 2; 3/2 + 1=5/2; 3; 5/2+1=7/2; 4; 5; 11/2;
у=√х-1: -1; -1/2; 0; 1/2; 1; 3/2; 2; 3; 7/2.
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у = 2х - 1 ; 3х + 5у = 8;
Подставим у = 2х - 1 во 2-е уравнение
3х + 5(2х - 1) = 8
3х + 10х - 5 = 8
13х = 13
х = 1 и у = 2 · 1 - 1 = 1
Ответ: (1; 1)
X^3+y^3=(x+y)(x^2-xy+y^2)
x^6+y^6+x^2+y^2=(x^2+y^2)(x^4-x^2y^2+y^4)+(x^2+y^2)=(x^2+y^2)(x^4-x^2y^2+y^4+1)