Привет!
(x²-9)/(x+3)²=(x+3)(x-3)/(x+3)²= x-3/x+3
{ 2x² + xy = 40
{ 3x - y = 10
{ y = 3x - 10
{ 2x² + x(3x - 10) = 40
5x² - 10x - 40 = 0
x² - 2x - 8 = 0 D = b²-4ac = 4+32 = 36
x₁ = (-b+√D)/2a = (2+6):2 = 4 y₁ = 3x - 10 = 2
x₂ = (-b-√D)/2a = (2-6):2 = -2 y₂ = 3x - 10 = -16
Ответ: {4; 2}; {-2; -16}
(2х-3)^3=8х^3-3•4х^2•3+3•2х•9-27
=8х^3-36х^2+54х-27
1) а²+2ab+b²-(c²-2cd+d²)=(a+b)²-(c+d)²
2)(х+a)²-(y+b)²
3) (a-d)²-(b+c)²