T=2π/k
k=π/2
T=2π:π/2=2π*2/π=4
X³+x²-xу²-y²=(х³+х²)-(ху²+у²)=х²(х+1)-у²(х+1)=
=(х+1)(х²-у²)=(х+1)(х-у)(х+у)
Log(6)x=log(6)(36a^5)
log(6)x=log(6)36+log(6)a^5
log(6)x=2+5log(6)a
Ответ:
Объяснение:
3) b²(a+1)-a²(b+1)=<u>ab²</u>+b²<u>-a²b</u>-a²=ab(b-a)+(b-a)(b+a)=(b-a)(ab+a=b);
4) (a-b)(b²-c²)-(b-c)(a²-b²)=(a-b)<em>(b-c)</em>(b+c)-<em>(b-c)</em>(a+b)(a-b)=<em>(a-b)(b-c)( b+c-a-b)</em>