(1+2sin a cos a )/ (sin a + cos a)=(sin² a + cos² a+2sin a cos a )/(sin a + cos a)=
= (sin a + cos a)²/ (sin a + cos a)=sin a + cos a
Logb(a) = loga(a) / loga(b)
поэтому
<span>logb(a) * loga(b) = loga(a) / loga(b) * loga(b) = loga(a) = 1</span>
-(11a+b)-(12a-3b)=-11a+b-12a+3b=-23a-3b