<span> 3x - y + 10 = 0
-2x + y - 7 = 0
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y = 3x + 10
y = 2x + 7
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3x + 10 = 2x + 7
3x - 2x = 7 - 10
x = - 3
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y = 2*( - 3 ) + 7 = - 6 + 7 = 1
Ответ ( - 3 ; 1 )
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10x^2+9x-9 = 0
D = 81-4*(-9)*10 = 81+360 = 441 (кв. корень равен 21)
х1 = (-9+21)/20 = 12\20 = 3\5 = 0,6
х2 = (-9-21)/20 = -30\20 = -3\2 = -1,5
<u> ax^2+bx+c = a(x-x1)(x-x2)</u>
10(x - 0,6)(х+1,5) = (10x-6)(x+1,5)<u>
</u><u>10x^2+9x-9 = (10x-6)(x+1,5)</u><u>
</u>
(1-cos(2x))/(6sinx)=(cos²x+sin²x-cos²x+sin²x)/(6sinx)=2sin²x/(6sinx)=sinx/3.
∫(sinx/3)dx=-cosx/3+C.