Question

Lim n-бес(5^1/n+5) / (7^1/n+2)

Answer 1

$\lim_{n \to \infty} (5^{1/n}+5) / (7^{1/n}+2) = (5^{1/ \infty}+5) / (7^{1/ \infty}+2) =$

$= (5^{0}+5) / (7^{0}+2) = \frac{6}{3} = 2$