<span>2x^2-4x+x-2=0
2x(x-2)+x-2=0
2x(x-2)+(x-2)=0
(x-2)(2x+1)=0
</span>
X/2-x-3/4<=1
2x-4x-3<=4
-2x<=4+3
-2x<=7
x>=-7/2
sin (arccos (-12/13)) решить.
3х(х√3-4х+6)=3х²√3-12х²+18х
(х-3)(2х+1)=2х²-5х-3
(4а-7b)(5a+6b)=20a²-11ab-42ab
(y+2)(y√2+y-8)=y²√2+y²-6y+2y√2-16