(-3.7;2) не помню точно но вроде так
<span> (4х+5)(3-х)=х^2 - 2х</span>
<span>23x - 4x^2 +15 - 5x - x^2 +2x = 0</span>
<span>-5x^2 +20x+15 = 0</span>
<span>-x^2 + 4x +3=0</span>
<span>a = -1</span>
<span>b = 4</span>
c = 3
Відповідь:
-8
Пояснення:
-2(2-у)(у+2)-2у²=2(у-2)(у+2)-2у²=2(у²-4-у²)=-8
1.149. ((x+3)/(x²-3x)+(x-3)/(x²+3x))·(9x-x³)/(x²+9)=
=((x+3)/x(x-3)+(x-3)/x(x+3))·x(9-x²)/(x²+9)=[((x+3)²+(x-3)²)/x(x²-9)]·x(9-x²)/(x²+9)=
=(x²+6x+9+x²-6x+9)·x·(9-x²)/(x(x²-9)·(x²+9)=(2·(x²+9)·x(9-x²))/(x·(x²-9)·(x²+9))=-2;
1.150 [(x+3)/(x-3)-(x-3)/(x+3)]:2x/(9-x²)=((x+3)²-(x-3)²)/(x²-9):2x/(9-x²)=
=(x²+6x+9-x²+6x-9)·(9-x²)/(2x·(x²-9))=(12x(9-x²)/2x(x²-9)=-6;
1.151 2a/(a+1)+(3/(a-1)²-3/(a²-1)):3/(a²-2a+1)=
=2a/(a+1)+[(3·(a+1)-3(a-1))/(a-1)²(a+1)]:3/(a-1)²=
=2a/(a+1)+(3a+3-3a+3)·(a-1)²/[3(a-1)²·(a+1)]=2a/(a+1)+6/3(a+1)=(2a+2)/(a+1)=2;
<span>Строим у=1/х
Сдвигаем ось оу на 1 единицу вправо
х -4 -2 -1 -1/2 -1/4 1/4 1/2 1 2 4
у -1/4 -1/2 -1 -2 -4 4 2 1 1/2 1/4</span>