Question

Решите неравенство. х+7 5+4х ----- > ----- 4 3

Answer 1

$\frac{x+7}{4} \ \textgreater \ \frac{5+4x}{3} |*12 \\ 3(x+7)\ \textgreater \ 4(5+4x) \\ 3x+21\ \textgreater \ 20+16x\\ -13x\ \textgreater \ -1 \\ x\ \textless \ \frac{1}{13}$

Answer 2

(x+7)/4>(5+4x)/3

3(x+7)>4(5+4x)

3x+21>20+16x

3x-16x>20-21

-13x>-1

13x<1

x<1/13


////////////о1/13_______

x принадлежит (-бесконечность; 1/13)