Прошу!Твой ответ готов!!!!!!!
A=v`(t)=-12sin(3t-π/6)
x(t)=F(v)=4/3*sin(3t-π/6)+C
4/3*sin(π-π/6)+C=5/3
4/3*1/2+C=5/3
C=5/3-2/3=1
x(π/3)=4/3*sin(3t-π/6)+1
v(π/3)=4cos5π/6 =-4*√3/2=-2√3
a(π/3)=-12sin5π/6=-12*1/2=-6
1) 4(x-5)-(7x+9)=1
4x-20-7x-9=1
-3x=30x / (-3)
x= -10
3) 0.3(6x+1.5)=2.7x-0.6(x-2)
1.8x+0.45=2.7x-0.6x+1.2
1.8x-2.7x+0.6x=1.2-0.45
-0.3x=0.75 / (-0.3)
x= -2.5
Ffffffffffffffffffffffffffffffffffff
5х/4 * 8/х = 40х/4х = 10.............