Question

Решите неравенство 3x^2-13x+12<0

Answer 1

$3 x^{2} -13x+12<0$
$x1.2=( 13+- \sqrt{169-12*4*3}):2=(13+- \sqrt{169-144} ):2$
$x1.2=(13+-5):2= \left \{ {{x1=9} \atop {x2=4}} \right.$