8y³-36y²+54y-27=0
(8y³-27)-<span>(36у</span>²-<span>54y)=0
(2у-3)(4у</span>²+6у+9)-18у(2у-3)=0
<span>(2у-3)(4у</span>²+6у+9-18у)=0
<span>(2у-3)(4у</span>²-12у+9)=0
<span>(2у-3)(2у-3)</span>²=0
<span>(2у-3)</span>³=0
<span>2у-3=0
2у=3
у=3:2
у=1,5
</span><span>
</span>
Решение:
(x+2)^2-34=x(x+1)
x^2+4+4x-34=x^2+x
3x=30
x=10
10, 11, 12.
(x-y)(x+y)-3(x+y)=(x+y)(x-y-3)