(x-1)(x²+x+1)-x²(x-1)=0
x³-1³-x³+x²=0
x²-1=0
(x-1)(x+1)=0
x-1=0 x+1=0
x₁=1 x₂=-1
Ответ: -1; 1
2log2(3)+log7(2)-log7(14)=2log2(3)+log7(2/14)=2log2(3)+log7(1/7)=2log2(3)-1=log2(9)-1
log7(1/7)=log7(7^-1)=-1*log7(7)=-1
<span>4(3y-1)² -18y(2y-1)=4(9у²-6у+1)-36у²+18у=36у²-24у+4-36у²+18у=-6у+4</span>