8-10х+15=13-6х
23-10х=13-6х
23-13=-6х+10х
10=4х
х=2.5
1) sin8x -√3cos8x = √3sin6x+cos6x ;
2sin(8x -π/3) =2sin(6x+π/6) ;
[ (8x -π/3)-(6x+π/6) =2πn ; (8x -π/3)+(6x+π/6) =π+2πn , n∈Z
[x=π/4 + πn ;x =π/12+ πn/7 , n∈Z
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2) cos2x =((1+√3)/2) *(cosx+sinx) ;
cos²x - sin²x =((1+√3)/2) *(cosx+sinx) ;
(cosx-sinx)(cosx+sinx) - ((1+√3)/2) *(cosx+sinx) =0 ;
(cosx+sinx)( cosx-sinx -(1+√3)/2) =0 ;
[ cosx+sinx =0 ;cosx-sinx =(1+√3)/2 .
[ tqx = -1 ;√2 * cos(x+π/4) =(1+√3)/2 .
[x = -π/4 +πn ; x +π/4 =±arccos(1+√3)/2√2 +2πn , n∈Z.
[x = -π/4 +πn ; x = -π/4±arccos(1+√3)/2√2 +2πn , n∈Z.
2x^2+14x-5x-35=0
2x^2+9x-35=0
D=b^2-4*ac
D=9^2-4*2*(-35)
D=81+280
D=361
D=19
x1,2=(-b+-<span>√D)/2a
x1=-9-19/2*2 x2=-9+19/2*2
x1=-28/4 x2=10/4
x1=-7 x2=2.5
Ответ: x1=-7; x2=2.5</span>
я уже сегодня решал надеюсь,что правильно