Question

Помогите с алгеброй!!! номер 52 ( а,б,в) номер 53(а,б)

Answer 1

52а)(n-1)/2n - (n+1)/5n= 5*(n-1)/10n - 2(n+1)/10n=(5n-5-2n-2)/10n=(3n-7)/10n б) 2/x-(1+y)/xy =2y/xy- (1+y)/xy=(2y-1-y)/xy = (y-1)/xy в)1/y^3 + (1-y^2)/y^5=y^2/y^5+(1-y^2)/y^5=( y^2-y^2+1)/y^5=1/y^5 53а)1/x+1/y+1/xy=y/xy+x/xy+1/xy=(x+y+1)/xy б)1/b^3-2/b^2+1/b=1/b^3-2b/b^3+b^2/b^3=(b^3-2b+1)/b^3