cos²(π/4)+sin(5π/6)-tg(π/4)=(√2/2)²+1/2-1=1/2+1/2-1=1-1=0.
-√2*sin(-5π/2+x)*sinx=cosx
√2cosx*sinx-cosx=0
cosx(√2sinx-1)=0
cosx=0⇒x=π/2+πn,n∈z
9π/2≤π/2+πn≤6π
9≤1+2n≤12
8≤2n≤11
4≤n≤5,5
n=4⇒x=π/2+4n=9π/2
n=5⇒x=π/2+5π=11π/2
√2sinx-1=0
sinx=1/√2
x=π/4+2πk U x=3π/4+2πm
9π/2≤π/4+2πk≤6π
18≤1+8k≤24
17≤8k≤23
17/8≤k≤23/8
нет решения
9π/2≤3π/4+2πm≤6π
18≤3+8m≤24
15≤8m≤21
15/8≤m≤21/8
m=2⇒x=3π/4+4π=19π/4
7x² +18x +5=0
x₁*x₂ = 5/7
x₁+x₂ = -18/7
x₁ = -18/7 - x₂
(-18/7 - x₂)*x₂= 5/7
-18/7 x₂ - x₂² - 5/7 =0
-18x₂ - 7x₂² -5=0
7x₂² +18x₂ +5 =0
D= 18² - 4*7*5 = 324 - 140 =184
x₂ =<u> -18 -√184 </u>= <u>-18 - 2√46</u> = <u>-9 -√46</u>
14 14 7
x₂ = <u>-9 +√46</u>
7
При х₂ = <u>-9-√46 </u>
7
х₁ =<u> -18</u> - <u> -9-√46 </u>= <u>-18+9+√46 </u>= <u>-9 +√46</u>
7 7 7 7
При х₂ = -9 +√46
х₁ =<u> -18 +9 -√46</u>= <u> -9-√46</u>
7 7
2 способ: более простой
7х²+18х+5=0
D=18² - 4*7*5=324-140=184
x₁ = <u>-18 -√184</u> =<u> -18 - 2√46</u> = <u> -9 - √46</u>
14 14 7
x₂ = <u>-9+√46</u>
7
{x+y=35
{3x-y=1
Складываем
4х=36
х=9
у=35-х
у=35-9
у=26
О т в е т. х=9; у=26
Х+2 = 4-2х
3х=2
х=2/3
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