(1) f(x) = x² + x = x(x + 1)
(2) f(x0 + ∆x) = f(1 + 0,2) = f(1,2) = 1,2(1,2 + 1) = 1,2 × 2,2 = 2,64
(3) f(x0) = f(1) = 1(1 + 1) = 1 × 2 = 2
(4) ∆f(x) = f(x0 + ∆x) - f(x0) = f(1,2) - f(1) = 2,64 - 2 = 0,64
Ответ: ∆f(x) = 0,64
1.
√144+5*√0,64=12+5*0,8=12+4=16.
(4√2)²=4²*(√2)²=16*2=32
√(0,16*25)-6*√(1/36)=0,4*5-6*(1/6)=2-1=1.
2.
√11*√44=√11*4√11=4*11=44
√(44/11)=√4=2
√6⁴=6²=36.
3.
√3(≈1,73) ____________2_____________3___________√13(≈3.6)
4.
-√(a⁴b⁶)=-a²b³
1.
7√3+√48+√27==7√3+4√3+3√3=14√3
√2*(√8+4√2)=√16+4*2=4+8=12
(√5-√3)²=5-2√15+3=8-√2√15
(√5-√3)(√5+√3)=5-3=2
2.
2√6∧4√2
√(4*6)∧√(16*2)
√24<√32
3.
(√3-3)/(3√2-√6)=(√3-3)(√2(3-√3)=-(3-√3)/(√2(3-√3)=1/√2√=√2*1/(√2)²=√2/2
4.
15/2√6=15*√6/(2√6*√6)=15*√6/12=5√6/4=1,25√6
19/(2√5-1)=19*(2√5+1)/((2√5-1)(2√5+1))=19*(2√5+1)/(4*5-1)=
=19*(2√5+1)/19=2√5+1.