х г 12г
ch3oh + ch3cooh = ch3cooch3 + h2o
32 60
n(ch3oh)=1моль
M(ch3oh)=12+4+16=32г/моль
m(ch3oh)=n*M=1*32=32г
n(ch3cooh)=1моль
M(ch3cooh)=12*2 + 16*2 + 4=60г/моль
m(ch3cooh)=60г
составляем пропорцию
x/32=12/60
x=32*12/60=6.4
m(ch3oh)=6.4 г
Ответ: 6.4 г
N=V/Vm
V=n*Vm=2.5*22.4=56 л
CH3-COOH + Cl2 -(Pкрасный)-> СH2(Cl)-COOH + HCl
СH2(Cl)-COOH + 2NH3 -> СH2(NH2)-COOH + NH4Cl
СH2(NH2)-COOH + CH3OH -(H2SO4)-> СH2(NH2)-COO-CH3 + H2O
4P+5O2 --- 2P2O5
P2O5 + 3Ba(OH) 2 --- Ba3(PO4)2 + 3H2O
Ba3(PO4)2 + 3HSO4 --- 2BaSO4 + 3H3PO4
H3PO4 + NaOH -- NaH2PO4 + H20
NaH2PO4 + NaOH -- Na2HPO4+H20
ДСО2(Н2О)=М(Н2О)/М(СО2)=18/44=0,4