=-(2a-1)(3a-1)/(2a-1)(2a+1)=(1-3a)/(2a+1)
1) 30 ^ n = ( 2•3•5 ) ^ n = ( 2 ^ n ) • ( 3 ^ n ) • ( 5 ^ n )
2) ( 2 ^ n ) : ( 2 ^ n + 2 ) = 2 ^ - 2 = 1/4
3) ( 5 ^ n ) : ( 5 ^ n - 2 ) = 5 ^ 2 = 25
Получили
( 3 ^ n ) • ( 1/4 ) • 25 = 6,25 • ( 3 ^ n )
1)3/х+3 + 3/х2-3х + 2х/9-х2=3/х+3 + 3/х(х-3) + 2х/(3-х)(3+х)=3•(х(х-3) + 3•(х+3) -2х•х/х(х+3)(х-3)= 3х2-9х+3х+9-2х2/х(х-3)(х+3)=х2-6х+9/х(х-3)(х+3)=(х-3)2/х(х-3)(х+3)=х-3/х2+3х
3)а^2-b/a-a=0,04+25-0,2=24,84
(3х + 5) + (8х + 1) = 17
3х + 5 + 8х + 1 = 17
3х + 8х = -5 -1 + 17
11х = 11
<u>х = 1</u>