<span>(m+5)^2-(m-4) (m+4)
</span>
m<span>^2+</span>10<span>m+25-</span>m<span>^2+16
10m+41
При m=-3,5:
10х(-3,5)+41=6
</span>
1) с^2-9=(c-3)(c+3)
<span>2) 25-n^2=(5-n)(5+n)</span>
F(x)=3x²-4x-4
f(0)=-4
f(3)=27-12-4=11
f'(x)=6x-4 6x-4=0 x=2/3
f(2/3)=3*4/9-4*2/3-4=12/9-24/9-4<0<11
наибольшее значение 11