∛48 *2*∛(-4) = ∛(48*(-4)) *2 = ∛ -4³ *2 = -4*2=-8
Пусть cosx=t, тогда 6t<span>^2+t+1=0
D=1-4(-6)=1+24=25
t1=(-1+5)/12=1/3
t2=(-1-5)/12=-1/2</span>
1)<span>cosa=u*(m+M)/mv=0.2*(80+720)/80*4=0,2*800/320=0,5
a=60гр
2)y`=8x-10+2/x=(8x²-10x+2)/x=0
2(4x²-5x+1)=0
D=25-16=9
x1=(5-3)/8=1/4∉[0;3;3]
x2=(5+3)/8=1∈[0,3;3]
y(0,3)=4*0,09-10*0,3+2ln0,3 -5≈0,36-3+2*(-1,2)-5≈-10,04
y(1)=4*1-10*1+2ln1-5=4-10+0-5=-11-наим
y(3)=4*9-10*3+2ln3-5≈36-30+2*1,1-5≈3,2</span>