S=12/3600*210=21/30<span>км= 700</span>
ОДЗ
x > 2
lg = log_10
log_10 (x - 2) > log_10 (1000)
x - 2 > 1000
x > 1002
+ ОДЗ
x > 1002
Ответ
<span>x </span>∈ ( 1002; + ∞)
3х²+12х+12
3(x^2+4x+4)
3*(x+2)^2
B3=b1*q²=1/2*1/4=1/8
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