Sin3x + sin5x = sin4x
2[sin((3x + 5x)/2)·cos(3x - 5x)/2)] = sin4x
2sin4xcosx - sin4x = 0
sin4x(2cosx - 1) = 0
sin4x = 0
4x = πn, n ∈ Z
x = πn/4, n ∈ Z
2cosx - 1 = 0
2cosx = 1
cosx = 1/2
x = ±π/3 + 2πk, k ∈ Z
Ответ: x = πn/4, n ∈ Z; ±π/3 + 2πk, k ∈ Z.
У=(-4^2)-4*(-4)=16-4*(-4)=16-(-16)=32
3^1*3^2*3^3=3^6 вычисляем корень 3 степени получим 3^2=9
1) 6х+8х-7х=714
14х-7х=714
7х=714
Х=714/7
Х=102
2) 23х-19х+5х= 1827
9х=1827
Х=1827/9
Х=203
3) 11х-6х+17=2042
5х=2042-17
5х=2025
Х=2025/5
Х=405
4) 5х+3х-47=6401
8х= 6401+47
8х=6448
Х=6448/8
Х=806