Question

Решите систему х-2у=1 2х-у=2 Пожалуйста)

Answer 1

$\left \{ {{x=1+2y} \atop {2(1+2y)-y=2}} \right. \left \{ {{x=1+2y} \atop {2+4y-y=2}} \right. \left \{ {{x=1+2y} \atop {3y=0}} \right. \left \{ {{x=1+2y} \atop {y=0}} \right. \left \{ {{x=1} \atop {y=0}} \right.$

Answer 2

X-2y=1
2x-y=2

x=1+2y
2(1+2y)-y=2

2(1+2y)-y=2
2+4y-y=2
3y=0
y=0

x=1+2*0=1

Ответ: (1;0)