1)5<span><span>(<span>a+b</span>)^</span>2</span>−10ab=5<span>(<span><span>a^2</span>+2ab+<span>b^2</span></span>)</span>−10ab= 5<span>a^2</span>+10ab+5<span>b^2</span>−10ab=5a^2+5b^2
2)<span><span>(<span>2b+<span>b^2</span></span>)^</span>2</span>+<span>b^2</span><span>(<span>5−b</span>)</span><span>(<span>5+b</span>)</span>−4b<span>(<span><span>b^2</span>−3</span>)= </span>4<span>b^2</span>+4<span>b^3</span>+<span>b^4</span>+<span>(<span><span>b^2</span>⋅5- <span>b^3</span></span>)</span><span>(<span>5+b</span>)</span>−4<span>b3</span>+12b= 4<span>b^2</span>+<span>b^4</span>+<span>(<span>5<span>b^2</span>−<span>b^3</span></span>)</span><span>(<span>5+b</span>)</span>+12b= =b^2+b^4+25b^2+5b^3−5b^3−b4+12b=29<span>b^2</span>+12<span>b</span>
Держи вроде все правильно)
^-знак возведения в степень
1.
1) = 9b^2-25
2) = 64y^2-25x^2
3) = 0,25x^6-0,04y^8
4) = x^14-y^6
5) = y^8n-y^2n
2. 1) -2y^2(3y+1)(1-3y)=-2y^2(1-9y^2)=18y^4-2y^2
2) = (a^10+b^10)(a^10-b^10)=a^20-b^20
3. =0= x^2-4-x^2+6x ---> x=4/6=2/3
4. 1) (3b-4x)(3b+4x)=9b^2-16x^2
2) (2a+7b)(2a-7b)=4a^2-49b^2
вот, тут нужно расскрыть скобки, и неизвестное в одной части оставить, а известное в другую