<span>y=2x </span>
<span>прямая y=kx проходит через центр координат</span>
2x²/(2x²+x-3) - 8/(2x²-3x-9) =1 ;
1 +(3-x)/(2x²+x-3) <span> - 8/(2x²-3x-9) =1 ;
</span><span>* * * ОДЗ: 2x²+x-3</span>≠0 ;2x²-3x-9 ≠0 ⇒x ≠-3/2 ,x≠1 ,x ≠3* * *
(3-x)(2x²-3x-9) -8(<span>2x²+x-3) =0 ;
</span>-2x³+3x²+9x +6x² -9x -27 -16x² -8x +24 =0 ;
-2x³-7x² -8x -3 =0 ;
2x³+ 7x²+8x+3 =0 ; * * * x = -1 корень * * *
(2x³+ 2x²)+(5x²+5x) +(3x<span>+3) =0 ;
</span>2x²(x+1) +5x(x+1) +3(x+1) =0 ;
<span>(x+1)(2x</span>²<span> +5x +3) =0 ;</span>
(x+1)²(2x+3) =0 ⇒[ x = -3/2 ; x= -1.
x = -3/2∉ <span>ОДЗ .
</span>
ответ: -1.
8х²+3х=0
x(8x + 3) = 0
x₁ = 0
8x + 3 = 0
8x = - 3
x₂ = - 3/8
2) 3х² - 8 = 0
3x² = 8
x² = 8/3
a) x = - √(8/3)
x₁ = (- 2/3)√6
b) x = √(8/3)
x₂ = ( 2/3)√6
3) 5u² - 6u = 0
u(5u - 6) = 0
u₁ = 0
5u - 6 = 0
u₂ = 6/5
u₂ = 1(1/5)
4) 2a - 4a² = 0
2a(1 - 2a) = 0
2a = 0
a₁ = 0
1 - 2a = 0
a₂ = 1/2
5) 1 - 16y² = 0
16y² = 1
y² = 1/16
y₁ = - 1/4
y₂ = 1/4
6) 2x² - 4 = 0
2x² = 4
x² = 2
x₁ = - √2
x₂ = √2