Question

Разложить на множители 1(целая) 24/25m^6n^4-1(целая) 9/16a^2b^8

Answer 1

$1 \frac{24}{25}m ^{6 } n ^{4} -1 \frac{9}{16}a ^{2} b ^{8} = \frac{49}{25} m^{6} n^{4} - \frac{25}{16} a^{2} b^{8}=( \frac{7}{5} m^{3} n^{2}) ^{2}-( \frac{5}{4}a b^{4}) ^{2}=$$( \frac{7}{5} m^{3} n^{2}- \frac{5}{4}a b^{4} )( \frac{7}{5} m^{3} n^{2} + \frac{5}{4}a b^{4})=(1,4 m^{3} n^{2}-1,25a b^{4})(1,4 m^{3} n^{2} +$$1,25a b^{4} )$

Answer 2

49/25*m^6n^4-25/16*a^2b^8=(7/5*m^3n^2-5/4*ab^4)(7/5*m^3n^2+5/4*ab^4)