<span>5.
y=-3x²-6x+7
</span><span><span>координаты вершины параболы
</span>x = -b/2a
х=6/2(-3) = -1
y=</span>-3(-1)²-6(-1)+7=-3+6+7=10
Ответ: <span>координаты вершины параболы (-1;10)</span>
(2*6^1/2)^2+(10^1/2)^2=(34^1/2)^2
(6^1/2)^2+(7^1/2)^2=(13^1/2)^2
(2*3^1/2)^2+3^2=(21^1/2)^2
1)7-2x-x^2)-(x-2)(x+3)=7-2x-x^2-x^2-x+6=-2x^2-3x+13
2)(3m^2+3n^2)-(2m+n)(m+2n)=3m^2+3n^2-2m^2-5mn-2n^2=m^2-5mn+n^2
3)u(u+v)-(v-1)(u-1)=u^2++uv-uv+v+u-1=u^2+v+u-1
4)x^2+1)(x^2+2)=x^4+2x^2+x^2+2=x^4+3x^2+2
5)3+b^3)(b^3-4)=3b^3-12+b^6-4b^3=b^6-b^3-12
16/25x^2-7y+2/10x
4/5x-7y+2/10x
8/10x-7y+2/10x
x+7y