Question

задание во вложении.решите хотябы 4 задание.ответ в нем-4\9

Answer 1

$(\frac{2}{x^{\frac{1}{3}}+y^{\frac{1}{3}}}+\frac{2}{x^{\frac{1}{3}}-y^{\frac{1}{3}}}):\frac{9x^{\frac{-1}{3}}y^{\frac{-2}{3}}}{x^{\frac{-2}{3}}-y^{-\frac{-2}{3}}}=\\ (\frac{2(x^{\frac{1}{3}}-y^{\frac{1}{3}})+2(x^{\frac{1}{3}}-y^{\frac{1}{3}})}{x^{\frac{2}{3}}-y^{\frac{2}{3}}})*\frac{x^{\frac{-2}{3}}-y^{-\frac{-2}{3}}}{9x^{\frac{-1}{3}}y^{\frac{-2}{3}}}=$

$\frac{2(x^{\frac{1}{3}}-y^{\frac{1}{3}}+x^{\frac{1}{3}}-y^{\frac{1}{3}})}{x^{\frac{2}{3}}-y^{\frac{2}{3}}}*\frac{x^{\frac{-2}{3}}-y^{-\frac{-2}{3}}}{9x^{\frac{-1}{3}}y^{\frac{-2}{3}}}=\\ \frac{2*2x^{\frac{1}{3}}}{x^{\frac{2}{3}}-y^{\frac{2}{3}}}*\frac{\frac{1}{x^{\frac{2}{3}}}-\frac{1}{y^{\frac{2}{3}}}}{9*\frac{1}{x^{\frac{1}{3}}}*\frac{1}{y^{\frac{2}{3}}}}=$

$\frac{4x^{\frac{1}{3}}}{x^{\frac{2}{3}}-y^{\frac{2}{3}}}*\frac{(y^{\frac{2}{3}}-x^{\frac{2}{3}})x^{\frac{2}{3}}x^{\frac{1}{3}}y^{\frac{2}{3}}}{9y^{\frac{2}{3}}}=\\ \frac{4x^{\frac{1}{3}}(y^{\frac{2}{3}}-x^{\frac{2}{3}})x^{\frac{1}{3}}y^{\frac{2}{3}}}{9(x^{\frac{2}{3}}-y^{\frac{2}{3}})x^{\frac{2}{3}}y^{\frac{2}{3}}}=\\ -\frac{4}{9}$