Question

Упростите выражение sin85°tg5°

Answer 1

$\sin85^\circ\mathop{\mathrm{tg}}5^\circ=\sin(90^\circ-5^\circ)\cdot\dfrac{\sin5^\circ}{\cos5^\circ}=\cos5^\circ\cdot\dfrac{\sin5^\circ}{\cos5^\circ}=\sin5^\circ$