Question

Дано : sin альфа = - 4/5 180 градусов < альфа < 270 градусов Найти cos альфа , tg альфа , ctg альфа

Answer 1

$\alpha\in(180^o;\ 270^o)\to sin\alpha;\ cos\alpha < 0\ \wedge\ tg\alpha;\ ctg\alpha > 0\\\\sin\alpha=-\frac{4}{5}\\\\sin^2\alpha+cos^2\alpha=1\\\\\left(-\frac{4}{5}\right)^2+cos^2\alpha=1\\\\\frac{16}{25}+cos^2\alpha=1\\\\cos^2\alpha=1-\frac{16}{25}\\\\cos^2\alpha=\frac{9}{25}\\\\cos\alpha=-\sqrt\frac{9}{25}\\\\cos\alpha=-\frac{3}{5}$


$tg\alpha=\frac{sin\alpha}{cos\alpha}\\\\tg\alpha=\left(-\frac{4}{5}\right):\left(-\frac{3}{5}\right)=\frac{4}{5}\cdot\frac{5}{3}=\frac{4}{3}\\\\ctg\alpha=\frac{1}{tg\alpha}\\\\ctg\alpha=\frac{1}{\frac{4}{3}}=\frac{3}{4}$