Question

(9/25)x+0,5<125/27 помогите решить пожалуйста

Answer 1

$\frac{9}{25} x+0,5\ \textless \ \frac{125}{27}$
25*27=675 
$\frac{9*27}{675} x+0,5*675\ \textless \ \frac{125*25}{675}$
$\frac{243}{675} x+337,5\ \textless \ \frac{3125}{675}$
$\frac{243}{675} x\ \textless \ \frac{3125}{675}-337,5$
$\frac{3125}{675}-337,5= \frac{3125}{675}- \frac{3375}{10} =\frac{31250}{6750}- \frac{2278125}{6750} = -\frac{2246875}{6750}=-332 \frac{5875}{6750} =$$-332 \frac{5875}{6750}$
$\frac{243}{675} x\ \textless \-332 \frac{5875}{6750}$
$x\ \textless \ \frac{-332 \frac{5875}{6750}}{\frac{243}{675}}$
$x\ \textless \ -332 \frac{5875}{6750}* \frac{675}{243}$
$x\ \textless \ -332 \frac{5875}{10}* \frac{1}{243}$
$x\ \textless \ -332 \frac{5875}{2430}$
$x\ \textless \ -(332+2 \frac{1015}{2430})$
$x\ \textless \ -334 \frac{203}{486}$
$x\ \textless \ -334,41769$
$x\ \textless \ -334,42$