Question

Решите уравнение:7-(х+ 1 целая 3/5)=2 целых 4/5

Answer 1

7-(х+1$\frac{3}{5}$)=2$\frac{4}{5}$
7-x-$\frac{8}{5}$=$\frac{14}{5}$
7-x=$\frac{14}5}$+$\frac{8}{5}$
7-x=$\frac{22}{5}$
-x=$\frac{22}{5}$-7
-x=$\frac{22-7*5}{5}$
-5x=22-35
5x=13
x=$\frac{13}{5}$
x=2$\frac{3}{5}$