1) 360 + А 2) Т : (5 * Т ) 3)x+(36+19) 4)А+(126-А) МОЖЕТ БЫТЬ ТАК НО Я НЕ УВЕРЕНА!!
8 1/2 , 1 4/5 , 3/25 , 3/5
![\sqrt{2x + 3} = x.](https://tex.z-dn.net/?f=+%5Csqrt%7B2x+%2B+3%7D++%3D+x.)
ОДЗ :
![1) \: 2x + 3 \geqslant 0 \\ 2x \geqslant - 3 \\ x \geqslant - 1.5 \\ 2) \: x \geqslant 0](https://tex.z-dn.net/?f=1%29+%5C%3A+2x+%2B+3+%5Cgeqslant+0+%5C%5C+2x+%5Cgeqslant++-+3+%5C%5C+x+%5Cgeqslant++-+1.5+%5C%5C+2%29+%5C%3A+x+%5Cgeqslant+0)
То есть хЄ [0 ; + бесконечность)
![( \sqrt{2x + 3} {)}^{2} = {x}^{2} \\ 2x + 3 = {x}^{2} \\ - {x}^{2} + 2x + 3 = 0 \\ {x}^{2} - 2x - 3 = 0 \\ x1 + x2 = 2. \: \: \: x1 \times x2 = - 3. \\ x1 = 3. \: \: \: x2 = - 1](https://tex.z-dn.net/?f=%28+%5Csqrt%7B2x+%2B+3%7D++%7B%29%7D%5E%7B2%7D++%3D++%7Bx%7D%5E%7B2%7D++%5C%5C+2x+%2B+3+%3D++%7Bx%7D%5E%7B2%7D++%5C%5C++-++%7Bx%7D%5E%7B2%7D++%2B+2x+%2B+3+%3D+0+%5C%5C++%7Bx%7D%5E%7B2%7D++-+2x+-+3+%3D+0+%5C%5C+x1++%2B+x2+%3D+2.+%5C%3A++%5C%3A++%5C%3A+x1+%5Ctimes+x2++%3D++-+3.+%5C%5C+x1+%3D+3.+%5C%3A++%5C%3A++%5C%3A+x2+%3D++-+1)
х2 = -1 - не удовлетворяет условие задачи;
ОТВЕТ:
х = 3.
19/20-x=5/12+6/12
19/20-x=11/12
x=19/20-11/12
x=57/60-55/60
x=2/60=1/30
Ответ: 1/30