[x²(x-3)-(x-3)]/[(x+1)(x+2)]>0
(x-3)(x²-1)/(x+1)(x+2)]>0
(x-3)(x-1)(x+1)/[(x+1)(x+2)]>0
(x-3)(x-1)/(x+2)>0,x≠-1
x=3 x=1 x=-2
_ + + _ +
--------(2) ---------(-1)-----------(1)----------(3)-----------
x∈(-2;-1) U (-1;1) U (3;∞)
С(5, 10) = 10*9*8*7*6 / (1*2*3*4*5) = 9*8*7*6 / (3*4) = 3*2*7*6 = 252
Х+7 -<u> х </u>=3
3
х -<u> х </u> =3-7
3
<u>3х-х </u>= -4
3
2х = -4*3
2х=-12
х=-6
Ответ: -6.