<span> возьмём за А - количество рядов </span>
<span>Б - количество фишек в каждом ряду </span>
![\ln(x^3-7x+2\sin x+3)=\ln(x^3-7x+2\sin x-4)](https://tex.z-dn.net/?f=%5Cln%28x%5E3-7x%2B2%5Csin+x%2B3%29%3D%5Cln%28x%5E3-7x%2B2%5Csin+x-4%29)
Пусть
![x^3-7x+2\sin x=t](https://tex.z-dn.net/?f=x%5E3-7x%2B2%5Csin+x%3Dt)
, тогда получаем
![\ln (t+3)=\ln (t-4)\\ t+3=t-4\\ 0=-7](https://tex.z-dn.net/?f=%5Cln+%28t%2B3%29%3D%5Cln+%28t-4%29%5C%5C+t%2B3%3Dt-4%5C%5C+0%3D-7)
Откуда не тождество, а значит уравнение решений не имеет.
Ответ: нет решений.
![\log_2( \sqrt{x-1}+ \sqrt{1-x} +2)=\log_2^7x+1](https://tex.z-dn.net/?f=%5Clog_2%28+%5Csqrt%7Bx-1%7D%2B+%5Csqrt%7B1-x%7D++%2B2%29%3D%5Clog_2%5E7x%2B1)
ОДЗ:
![\begin{cases} & \text{ } 1-x \geq 0 \\ & \text{ } x-1 \geq 0 \\ & \text{ } \sqrt{1-x}+ \sqrt{1-x}+2 \ \textgreater \ 0 \\ & \text{ } 1-x \geq 0 \end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%0A%26+%5Ctext%7B+%7D+1-x+%5Cgeq+0+%5C%5C+%0A%26+%5Ctext%7B+%7D+x-1+%5Cgeq+0+%5C%5C+%0A%26+%5Ctext%7B+%7D++%5Csqrt%7B1-x%7D%2B+%5Csqrt%7B1-x%7D%2B2+%5C+%5Ctextgreater+%5C+0+++%5C%5C+%0A%26+%5Ctext%7B+%7D+1-x+%5Cgeq+0+%0A%5Cend%7Bcases%7D)
так как
![\begin{cases} & \text{ } x-1 \geq 0 \\ & \text{ } 1-x \leq 0 \end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%0A%26+%5Ctext%7B+%7D+x-1+%5Cgeq+0+%5C%5C+%0A%26+%5Ctext%7B+%7D+1-x+%5Cleq+0+%0A%5Cend%7Bcases%7D)
, то можно сделать уравнение таким образом
![\begin{cases} & \text{ } x\ \textgreater \ 0 \\ & \text{ } 1-x=0 \\ & \text{ } \sqrt{x-1}+ \sqrt{1-x}+2\ \textgreater \ 0 \\ & \text{ } \log_2( \sqrt{x-1}+ \sqrt{1-x}+2)=\log_2^7x+1 \end{cases}\Rightarrow\begin{cases} & \text{ } 1\ \textgreater \ 0 \\ & \text{ } x=1 \\ & \text{ } 2\ \textgreater \ 0 \\ & \text{ } 1=1 \end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%0A%26+%5Ctext%7B+%7D+x%5C+%5Ctextgreater+%5C+0+%5C%5C+%0A%26+%5Ctext%7B+%7D+1-x%3D0+%5C%5C+%0A%26+%5Ctext%7B+%7D++%5Csqrt%7Bx-1%7D%2B+%5Csqrt%7B1-x%7D%2B2%5C+%5Ctextgreater+%5C+0+++%5C%5C+%0A%26+%5Ctext%7B+%7D+%5Clog_2%28+%5Csqrt%7Bx-1%7D%2B+%5Csqrt%7B1-x%7D%2B2%29%3D%5Clog_2%5E7x%2B1+++%0A%5Cend%7Bcases%7D%5CRightarrow%5Cbegin%7Bcases%7D%0A%26+%5Ctext%7B+%7D+1%5C+%5Ctextgreater+%5C+0+%5C%5C+%0A%26+%5Ctext%7B+%7D+x%3D1+%5C%5C+%0A%26+%5Ctext%7B+%7D+2%5C+%5Ctextgreater+%5C+0+%5C%5C+%0A%26+%5Ctext%7B+%7D+1%3D1+%0A%5Cend%7Bcases%7D)
Ответ: x=1