Question

Please: представте в виде квадрата двучлена:4+4a+a^2= y^2-14y+49= c^4-4c^2d+4d^2= 20cn+25c^2+4n^2= 1+81x^2-18x=

Answer 1

4+4a+a²=(2+a)²
y²-14y+49=(y-7)²
c⁴-4c²d+4d²=(c²-2d)²
20cn+25c²+4n²=(5c+2n)²
1+81x²-18x=(1-9x)²

Answer 2

$1. (2+a)^{2} \\ 2. (y-7)^{2} \\ 3.(c^{2}-2d)^{2} \\ 4.(2n+5c)^{2} \\ 5.(9x-1)^{2}$