Log(0*5) 125/log(0.5) 5=log(0.5) 5^3/log(0.5)5=3*log(0.5)5/ log(0.5) 5=3
<EMN=<KME+<KMN=<ABE+<KMC/2=<ABE+(180-<ABE)/2=34+73=107
у^20/у^5=у^15_____________
(-6*2\15-1\12+5\6)\0,5+0,5=(-12\15-1\12+5\6)\0,5+0,5=(-12*72-90+180\180)\0,5+0,5=(-774\180)\0,5+0,5=-4,3\0,5+0,5=-8,6+0,5=-8,1
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