(√5x-√6)*(√5x+√6)/(√6-√5x)= -√5x-√6
![\frac{x+3.4}{10x-9} = \frac{x+3.4}{9x-10}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx%2B3.4%7D%7B10x-9%7D+%3D+%5Cfrac%7Bx%2B3.4%7D%7B9x-10%7D+)
(x+3.4)(9x-10)=(x+3.4)(10x-9)
9x²-10x+30.6x-34=10x²-9x+34x-30.6
10x²-9x+34x-30.6-9x²+10x-30.6x+34=0
x²+4.4x+3.4=0
D=4.4²-4*3.4=19.36-13.6=5.76=2.4²
x(1)=(-4.4+2.4)/2=-2/2=-1
x(2)=(-4.4-2.4)/2=-6.8/2=-3.4
меньший корень -3.4
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(3-3x²)`=-6x
-6x=0
x=0
+ _
-----------------(0)------------------
возр убыв
т.к sqrt(7) получить 7 надо возвести в квадрат, еще 7^2=49