Question

Sin3x=cosx-sinx решите плиз

Answer 1

Sin3x+sinx=cosx
2sin2xcosx-cosx=0
cosx*(2sin2x-1)=0
cosx=0⇒x=π/2+πk,k∈z
sin2x=1/2⇒2x=π/6+2πk U 2x=5π/6+2πk⇒x=π/12+πk,k∈z U x=5π/12+πk,k∈z