1)y'(x)=6x^2-3-3x^(-4), подставим x=1, y'(1)=6-3-3=0
2)y'(x)=-12x^(-5)-6x^(-1/4), y'(2)=-12/(2^5)-6/
![\sqrt[4]{2}](https://tex.z-dn.net/?f=+%5Csqrt%5B4%5D%7B2%7D+)
=-0,375-
![\frac{6}{ \sqrt[4]{2} }](https://tex.z-dn.net/?f=+%5Cfrac%7B6%7D%7B+%5Csqrt%5B4%5D%7B2%7D+%7D+)
3)y'(x)=-1/(x^5)+1/2x, y'(1)=-1+0.5=-0,5
4)y'(x)=(5xe^x+4x^(-3))'=5e^x+5xe^x-12x^(-4)=(e^x)(5+5x)-12x^(-4)
y'(1)=10e-12
5)y'(x)=(4x^3)/3 *
![\sqrt{1-4x}](https://tex.z-dn.net/?f=+%5Csqrt%7B1-4x%7D+)
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![\frac{2 x_{4} }{3 \ \sqrt{1-4x} }](https://tex.z-dn.net/?f=+%5Cfrac%7B2+x_%7B4%7D+%7D%7B3+%5C+%5Csqrt%7B1-4x%7D+%7D+)
y'(1)= не существует при х=1