4ху² = 2у² (2х - 1)
Надеюсь, помогла :)
(bn)- геом. прогр.
b1=27
b3=3
q-?
bn²=bn-1*bn+1
b2=√27*3=9
q=bn+1:bn
q=1:3
=(2^(3)^(-3))*2^(5)*(5^5)÷(5^6)*(2*^(-2)=(2^(-9)*(2^5)*(5^5))/(5^6)*(2^(-2))=2^(-4)*(5^5)/(5^6)*(2^-2)=2^(-2)*5^(-1)=1/4*1/5=1/20
(-3.25-2.75)÷(-0.6)+0.8×(-7)= (-6)÷(- 0.6)+0.8×(-7)= 10+0.8×(-7)= 10+(-5,6)= 10-5.6= 4.4