Sin8x\sin4x - 2cos(в степени 2 ) 2x = 2*sin4x*cos4x\sin4x - 2* (1+cos4x)\2= 2cos4x -1 - cos4x = cos4x - 1
О,5x²-0,1x-10 = о,5*(-4)²-0,1*(-4)-10 = <span>о,5*16+0,4-10 = 8-9,6 = -1,6</span>
sin12 * cos78 + sin102 * cos12 = sin12 * cos(90-12) + sin(90+12) * cos12 = (далее по формулам приведения) sin12 * sin12 + cos12 * cos12 = sin^2 12 + cos^2 12 = 1