Question

Lim x-1 3x^3-3/x^2-x

Answer 1

$\lim_{x\rightarrow 1 } \dfrac{3x^3-3}{x^2-x}=\lim_{x\rightarrow 1 } \dfrac{3(x-1)(x^2+x+1)}{x(x-1)}= \\ \\ = \lim_{x\rightarrow 1 } \dfrac{3(x^2+x+1)}{x}= \lim_{x\rightarrow 1 } \dfrac{3 \cdot 3}{1}=9.$