Question

∛(3^(x+1) )=(∜(9^(x-2)))

Answer 1

$\sqrt[3]{3^{x+1}} = \sqrt[4]{9^{x-2}}$
$3^{ \frac{x+1}{3}} =3^{ \frac{2(x-2)}{4} }$
$\frac{x+1}{3} = \frac{x-2}{2}$
2x + 2 = 3x - 6
2x - 3x = -6 - 2
x = 8.