Question

Помогите решить 3;2 и 4. Дам 30 баллов! На листочке!!!

Answer 1

$1)\; \; \frac{ \frac{3}{4}-\frac{5}{8}+\frac{1}{6}}{\frac{3}{8}+\frac{7}{12}-\frac{1}{2}}=\frac{\frac{18-15+4}{24}}{\frac{9+14-12}{24}}=\frac{7}{11}$

$2)\; \; 5+ \frac{4}{2-\frac{1}{3}}=5+\frac{4}{\frac{6-1}{3}}=5+\frac{4}{\frac{5}{3}} =5+\frac{4\cdot 3}{5} =5+\frac{12}{5}= \frac{25+12}{5}=\\\\= \frac{37}{3}=12\frac{1}{3}$

$3)\; \; \frac{3+ \frac{\frac{1}{2}-\frac{1}{5}}{3} }{7-\frac{4}{5}}= \frac{3+\frac{\frac{5-2}{10}}{3}}{\frac{35-4}{5}} = \frac{3+\frac{3}{10\cdot 3}}{\frac{31}{5}} = \frac{3+\frac{1}{10}}{\frac{31}{5}}= \frac{\frac{30+1}{10}}{\frac{31}{5}} = \frac{31\cdot 5}{10\cdot 31}=\frac{5}{10}=\frac{1}{2}$

$4)\; \; 2+ \frac{3}{2-1\frac{1}{2}}=2+\frac{3}{2-\frac{3}{2}}=2+\frac{3}{\frac{4-3}{2}} =2+ \frac{3}{\frac{1}{2}} =2+ \frac{3\cdot 2}{1}=2+6=8$